Question

Find the roots of the quadratic equation $2x^2-7x+3=0$ using quadratic formula. Select all the correct options.

• A. $x=\frac{3}{2}$
• B. $x=\frac{1}{2}$
• C. $x=3$
• D. $x=2$

Answer 1

Answer: (B), (C)

The correct options are
B $x=\frac{1}{2}$
C $x=3$

$2x^2-7x+3=0$

On comparing this equation with $a{x}^2+bx+c=0$, we get
a = 2, b = -7 and c = 3

By using quadratic formula, we get,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\Rightarrow$ $x=\frac{7\pm \sqrt{7^2-4\times 2\times 3}}{2\times 2}$

$\Rightarrow$ $x=\frac{7\pm \sqrt{49-24}}{2\times 2}$

$\Rightarrow$ $x=\frac{7\pm \sqrt{25}}{4}$

$\Rightarrow x=\frac{7\pm 5}{4}$

$\Rightarrow x=\frac{7+5}{4},x=\frac{7-5}{4}$

$\Rightarrow x=\frac{12}{4},\frac{2}{4}$

$\therefore x=3,\frac{1}{2}$