Find the roots of the quadratic equation a x2-b x-c-0A- x-b-b2-4-4aB- x-b-b2-4-4 aC- x-b -b2-4-2 aD - x - b - b 2-4 ac -2

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Solving Using Quadratic Formula When D>0

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Question

Find the roots of the quadratic equation $a x^{2} + b x + c = 0$ .

x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2}

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x = \frac{- b + \sqrt{b^{2} - 4 a c}}{4 a}

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x = \frac{- b - \sqrt{b^{2} - 4 a c}}{4 a}

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x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}

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Solution

The correct option is D $x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
The formula for the roots of the quadratic equation $a x^{2} + b x + c = 0$ is given as

$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$

$\frac{- b + \sqrt{b^{2} - 4 a c}}{2 a} a n d \frac{- b - \sqrt{b^{2} - 4 a c}}{2 a} are the roots of the equation.$

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Similar questions

Q. What are the roots of the quadratic equation

a x^{2} + b x + c = 0 ?

Q. Which of the given formulae is the correct one to find out the roots of the quadratic equation

a x^{2} + b x + c = 0

If b² – 4ac = 0 then The roots of the Quadratic equation ax² + bx + c = 0 are given by :

The roots of a quadratic equation $a x^{2} + b x + c = 0$ are given by $\frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ , provided $b^{2} - 4 a c \geq 0$ .

Q. What is the nature of the roots of the quadratic equation

a x^{2} + b x + c = 0

if
(a)

b^{2} - 4 a c = 0

(b)

b^{2} - 4 a c < 0

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Find the roots of the quadratic equation ax2+bx+c=0.

The correct option is D x=−b±√b2−4ac2aThe formula for the roots of the quadratic equation ax2+bx+c=0 is given as x=−b±√b2−4ac2a −b+√b2−4ac2a and −b−√b2−4ac2a are the roots of the equation.

Find the roots of the quadratic equation $a x^{2} + b x + c = 0$ .