Find the roots of the quadratic equation ax2+bx+c in terms of a, b, c
ax2+bx+c=0(a≠0)
Dividing throughout by a
x2+bax+ca=0
⇒(x+b2a)2−(b2a)2+ca=0
⇒(x+b2a)2−b2−4ac4a2=0
⇒(x+b2a)=±√b2−4ac4a2
⇒(x+b2a)=±√b2−4ac2a
x = −b2a±√b2−4ac2a
x = −b±√b2−4ac2a