CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
183
You visited us 183 times! Enjoying our articles? Unlock Full Access!
Question

Find the roots of the quadratic equation ax2+bx+c in terms of a, b, c

Open in App
Solution

ax2+bx+c=0(a0)

Dividing throughout by a

x2+bax+ca=0

(x+b2a)2(b2a)2+ca=0

(x+b2a)2b24ac4a2=0

(x+b2a)=±b24ac4a2

(x+b2a)=±b24ac2a

x = b2a±b24ac2a

x = b±b24ac2a


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE using Quadratic Formula
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon