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Question

Find the roots of the quadratic equation x22ax+a2b2c2=0 , where a,b,cR

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Solution

Consider the given equation.

x22ax+a2b2c2=0 …….. (1)

Let α,β are the roots of given equation.

α+β=BA=2a ……. (2)

αβ=CA=a2b2c2 …….. (3)

Since, (αβ)=(α+β)24αβ

(αβ)=(2a)24(a2b2c2)

(αβ)=4a24a2+4b2+4c2

(αβ)=4b2+4c2

(αβ)=2b2+c2 ……. (4)

On adding equation (2) and (4), we get

2α=2a+2b2+c2

α=a+b2+c2

On putting the value of α in equation (2), we get

β=ab2+c2

Hence, this is the answer.


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