Find the roots of the quadratic equation $x^{2} + 4 x - 12 = 0.$

6 and - 2

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- 6 and 2

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- 4 and 3

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3 and 4

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Solution

The correct option is B - 6 and 2
$x^{2} + 4 x - 12 = 0$
$\Rightarrow x^{2} + 6 x - 2 x - 12 = 0$
$\Rightarrow x (x + 6) - 2) (x + 6) = 0$
$\Rightarrow (x - 2) (x + 6) = 0$
Thus, the required roots are x = 2, x = - 6,

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