Question

Find the roots of $x^2+2\sqrt{2}x-6=0$ .

Answer 1

Now,

$x^2+2\sqrt{2}x-6=0$

or, $x^2+3\sqrt{2}x-\sqrt{2}x-6=0$

or, $(x+3\sqrt{x})(x-\sqrt{2})=0$

or, $x=-3\sqrt{2},\sqrt{2}$.