Question

Find the roots of
$x^2+6x+16=0$

Answer 1

We have,

$x^2-6x-16=0$

$x^2-8x+2x-16=0$

$x(x-8)+2(x-8)=0$

$(x-8)(x+2)=0$

$\therefore x-8=0$, $x+2=0$

$x=8$, $x=-2$

$\therefore x=8,-2$

Hence, this is answer.