Question

Find the roots of $x^2-3x-10=0$

Answer 1

Finding the roots of the equation

Given equation $x^2-3x-10=0$
$$\begin{gathered} \Rightarrow x^2-3x-10=0 \\ \Rightarrow x^2-(5-2)x-10=0 \\ \Rightarrow x^2-5x+2x-10=0 \\ \Rightarrow x(x-5)+2(x-5)=0 \\ \Rightarrow (x-5)(x+2)=0 \\ \Rightarrow x=5,-2 \end{gathered}$$

Hence the required roots are $5\&-2$