Find the roots x2 -2 -1x - -2 - 0

x^2 (√(2)+1)x+√(2)=0 x^2 √(2)x x+√(2)=0 x(x √(2)) 1(x √(2))=0 (x 1)(x √(2))=0 x=1, √(2) . ...

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Solving a Quadratic Equation by Factorization Method

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Question

Find the roots
$x^{2} - (\sqrt{2} + 1) x + \sqrt{2} = 0$

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∣ ∣ ∣ ∣ \begin{matrix} x 2 - 3 \end{matrix} \begin{matrix} - 6 - 3 x 2 x \end{matrix} \begin{matrix} - 1 x - 3 x + 2 \end{matrix} ∣ ∣ ∣ ∣ = 0

x^{2} - (\sqrt{2} + 1) x + \sqrt{2} = 0

\sqrt{2}

1

x^{2} - (\sqrt{2} + 1) x + \sqrt{2} = 0

f (x) = \int_{1}^{x} \sqrt{2 - t^{2}} d t .

x^{2} - f^{'} (x) = 0

2 - \sqrt{3}

x^{2} + 2 (\sqrt{3} - 1) x + 3 - 2 \sqrt{3} = 0

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