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Question

Find the second order derivative of the function y=log x

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Solution

Finding dydx
Let y=log x
Differentiating both sides w.r.t. x we get
dydx=d(log x)dx
dydx=1x(i)

Finding d2ydx2
Again, differentiating both sides of (i) w.r.t. x, we get
ddx(dydx)=ddx(1x)
d2ydx2=d(x1)dx
d2ydx2=1.x11
d2ydx2=x2
d2ydx2=1x2

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