Find the set of values of x for which the functions f(x)=3x2−1 and g(x)=3+x are equal.
∵f(x)=g(x)⇒3x2−1=3+x⇒3x2−x−4=0⇒3x2−4x+3x−4=0⇒x(3x−4)+1(3x−4)=0⇒(3x−4)(x+1)=0∴x=−1,43