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Question

Find the shortest distance between the lines.
r=^i+2^j+^k+λ(^i^j+^k)
r=2^i^j^k+μ(2^i+^j+2^k)

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Solution

a1=^i+2^j+^k;b1=^i^j+^k
a2=2^i^j^k;b2=2^i+^j+2^k
(a2a1)=^i3^j2^k
b1×b2=∣ ∣ ∣^i^j^k111212∣ ∣ ∣=3^i+3^kb1×b2=18
(b1×b2).((a2a1))=(3^i+3^k).(^i3^j2^k)=36=9
d=∣ ∣ ∣(b1×b2).((a2a1))(b1×b2)∣ ∣ ∣=918=32

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