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Question

Find the shortest distance between the skew lines r=(6i+2j+2k)+t(i2j+2k) and r=(4ik)+s(3i2j2k).

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Solution

r=(6ˆi+2ˆj+2ˆk)+t(ˆi2ˆj+2ˆk)r=(4ˆiˆk)+s(3ˆi2ˆj2ˆk)Shortestdistanced=(10ˆi+2ˆj+3ˆk).(ˆi2ˆj+2ˆk)×(3ˆi2ˆj2ˆk)(ˆi2ˆj+2ˆk)×(3ˆi2ˆj2ˆk)∣ ∣ ∣ˆiˆjˆk122322∣ ∣ ∣=ˆi(4+4)ˆj(26)+ˆk(2+6)=8ˆi+8ˆj+4ˆk=(10ˆi+2ˆj+3ˆk).(8ˆi+8ˆj+4ˆk)64+64+16Shortestdistane=80+16+12144=10812=9

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Shortest Distance between Two Skew Lines
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