Question

Find the shortest distance between the $x^2+y^2=9$ and $(6,8)$ is

Answer 1

The center of circle is $(0,0)$

The distance from $(6,8)$ is $\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10$

The radius of circle is $3$

So the shortest distance is given as $10-3=7$ units