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Question
Find the simple interest of ₹ 2000 from Jan 12, 2012, to October 30, 2012, at an interest of 10% per annum.
Find the simple interest of ₹ 2000 from Jan 12, 2012, to October 30, 2012, at an interest of 10% per annum.
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Solution
The correct option is A ₹ 160
Given P = ₹ 2000
R = 10%
To calculate time (T)
Jan - (31 - 12) = 19 days
Feb - 29 days (leap year)
March - 31 days
April - 30 days
May - 31 days
June - 30 days
July - 31 days
August - 31 days
September - 30 days
October - 30 days
Total 292 days =292365 year = 45 years
S. I =P×R×T100=2000×10×4100×5=₹ 160
₹ 160
Given P = ₹ 2000
R = 10%
To calculate time (T)
Jan - (31 - 12) = 19 days
Feb - 29 days (leap year)
March - 31 days
April - 30 days
May - 31 days
June - 30 days
July - 31 days
August - 31 days
September - 30 days
October - 30 days
Total 292 days =292365 year = 45 years
S. I =P×R×T100=2000×10×4100×5=₹ 160
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