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Question

Find the sixth term of expansion of (y12+x13)n, If third term from end is 45.

A
252x52y53
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B
252y12x13
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C
252y52x53
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D
14y52x53
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Solution

The correct option is C 252y52x53
Here, the general term, Tr+1=nCryr2xnr3
Total terms =n+1
3rd term from last is (n+1)3+1 or (n1) term from first.
Now, T(n2)+1=nCn2yn22x23Tn1=nC2yn22x23

The coefficient of (n1) term is 45.
So, nC2=45n(n1)2=45n=10


Now, the 6th term is
T6=10C5y1052x53
=252.y52x53

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