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Question

# Find the size distance and Nature of image formed of an object size 1cm height a distance 15cm infront of concave mirror of focal length.

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Solution

## Focal length is not given in the question.But I have seen this question before and the value of focal length=10 cm.This information is missing and please make a note that focal length=10 cm. The given mirror is a concave mirror ,thus by sign convention it's focal length will be negative. f = -10 cm u = -15cm h(height of object) = 1cm we have to find size , nature , distance of image formed . Thus using mirror equation :- 1/f = 1/u+1/v =>1/v = 1/f-1/u => 1/v = -1/10+1/15 => 1/v = -1/30 => v = -30 cm{ thus image will be formed at a distance of 30 cm in front of the mirror} Now magnification m = -(v/u) = h'/h m = -(-30/-15) => m = -2 HENCE the nature of image formed will be real and inverted (due to negative sign)and magnified. Now m = h'/h 2 = h'/1 => h' = 2cm hence the size of the image will be doubled.

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