Find the size of the class interval in the following:

(a) 11 − 20

(b) 31 − 35

(c) 41 − 49

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Solution

(a) Size of the class interval = (20 − 11) + 1 = 10

(b) Size of the class interval = (35 − 31) + 1 = 5

(c) Size of the class interval = (49 − 41) + 1 = 9

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Distance(km)	$1 - 11$	$11 - 21$	$21 - 31$	$31 - 41$	$41 - 51$
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Draw a frequency polygon for the following frequency distribution:
$\begin{matrix} Class interval & 1 - 10 & 11 - 20 & 21 - 30 & 31 - 40 & 41 - 50 & 51 - 60 Frequency & 8 & 3 & 6 & 12 & 2 & 7 \end{matrix}$

How to find the size of class interval

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Find the size of the class interval in the following: (a) 11 − 20 (b) 31 − 35 (c) 41 − 49

(a) Size of the class interval = (20 − 11) + 1 = 10 (b) Size of the class interval = (35 − 31) + 1 = 5 (c) Size of the class interval = (49 − 41) + 1 = 9

Find the size of the class interval in the following:

(a) 11 − 20

(b) 31 − 35

(c) 41 − 49

(a) Size of the class interval = (20 − 11) + 1 = 10

(b) Size of the class interval = (35 − 31) + 1 = 5

(c) Size of the class interval = (49 − 41) + 1 = 9