Find the slant height of a cone whose,
Base radius $= 14 c m$ , height $0.48 m$
Base diameter $= 70 c m$ , curved surface area $= 4070 c m^{2}$

52 c m; 37 c m

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50 c m; 37 c m

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51 c m; 37 c m

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50 c m; 36 c m

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Solution

The correct option is B $50 c m; 37 c m$
$r a d i u s = 14 c m, h e i g h t = 0.48 m = 48 c m$
$s l a n t h e i g h t^{2} = r a d i u s^{2} + h e i g h t^{2}$
$l^{2} = 14^{2} + 48^{2}, l^{2} = 2500, l = 50 c m$
radius=35 cm, curved surface area=4070 $= π r l$
$l = \frac{4070}{π (35)} = 37 c m$

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