Find the slope and $y$ intercept formed by line $7 x - 8 y + 1 = 0$ .

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Solution

Finding the slope and the $y$ intercept:
The given equation of line is $7 x - 8 y + 1 = 0$
On Rearranging the $7 x - 8 y + 1 = 0$ to the general form of line as $y = m x + c$ where $m$ is slope and $c$ is $y$ intercept , we get
$7 x - 8 y + 1 = 0$
$\Rightarrow 8 y = 7 x + 1$
$\Rightarrow y = \frac{7 x + 1}{8}$
$\Rightarrow y = \frac{7}{8} x + \frac{1}{8}$
Compare the above equation with general form, we get,
$m = \frac{7}{8}$ and $c = \frac{1}{8}$
Hence, the slope and $y$ intercept formed by line $7 x - 8 y + 1 = 0$ is $\frac{7}{8}$ and $\frac{1}{8}$ respectively.

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