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Byju's Answer
Standard XII
Mathematics
Particular Solution of a Differential Equation
Find the slop...
Question
Find the slope normal to the curve
x
2
/
3
+
y
2
/
3
=
2
at the point (1, 1).
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Solution
On differentiating the equation wrt
x
, we have
2
3
x
−
1
3
+
2
3
y
−
1
3
d
y
d
x
=
0
∴
d
y
d
x
=
−
(
x
y
)
−
1
3
This is the slope of the tangent at any point on given curve. The slope of normal
=
−
d
x
d
y
=
(
x
y
)
1
3
Hence, slope of normal at
(
1
,
1
)
is
1
.
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Particular Solution of a Differential Equation
Standard XII Mathematics
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