Find the slope of a line perpendicular to a line x+3y+1 = 0 and passing through (5, 12).
3

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Solution

The correct option is A 3
Product of the slopes of any two perpendicular lines is -1.
Slope of a line of the equation ax + by + c = 0 is $- \frac{a}{b}$ .
So, slope of the given line x+3y+1=0 is $- \frac{1}{3}$ .
Let the slope of the required line be 'm'.
$m \times - \frac{1}{3} = - 1 \to m = 3$ .

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