Find the slope of equation of the straight line passing through origin and the point of intersection of the lines $x + 2 y = 7 a n d x - y = 4$ .
0.2

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Solution

The correct option is A 0.2
Given,
The equations are $x + 2 y = 7$ .. (i)
$x - y = 4$ .. (ii)

Subtracting (ii) from (i),
$3 y = 3$
$y = 1$ .. (iii)

Putting (iii) in (ii)
$x - 1 = 4$
$x = 5$

$∴$ The point of intersection is (5, 1)
As, the other point lies in the origin (0,0) so,
The slope, $m = \frac{1 - 0}{5 - 0}$
$m = \frac{1}{5} = 0.2$

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Find the slope of equation of the straight line passing through origin and the point of intersection of the lines x+2y=7 and x–y=4.0.2

The correct option is A 0.2Given, The equations are x+2y=7 .. (i) x–y=4 .. (ii) Subtracting (ii) from (i), 3y=3 y=1 .. (iii) Putting (iii) in (ii) x−1=4 x=5 ∴ The point of intersection is (5, 1) As, the other point lies in the origin (0,0) so, The slope, m=1−05−0 m=15=0.2

Find the slope of equation of the straight line passing through origin and the point of intersection of the lines $x + 2 y = 7 a n d x - y = 4$ .
0.2