Find the slope of the line inclined at an angle of 135∘ with positive direction of x-axis
Slope of line m=tanθ
Here, θ=135∘
m=tan135∘
=tan(90∘+45∘)
=− cot 45∘=−1
So, slope of the line is −1
Find the equation of a line passing through (2, 3) and inclined at an angle of 135∘ with the positive direction of x-axis
Find the equation of the line which intercepts a length 2 on the positive direction of the x-axis and is inclined at an angle of 135∘ with the positive direction of y-axis.