Question

Find the slope of the line joining the points $(0,0)$ and $(\sqrt{3},3)$.

Answer 1

We know that the slope of the line joining two points $(x_1,y_1)$ and $(x_2,y_2)$ is:

$m=\frac{y_2-y_1}{x_2-x_1}$

Here, the given points are $(0,0)$ and $(\sqrt{3},3)$, therefore, the slope of the line is:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{3-0}{\sqrt{3}-0}=\frac{3}{\sqrt{3}}=\frac{3\times \sqrt{3}}{\sqrt{3}\times \sqrt{3}}=\frac{3\sqrt{3}}{3}=\sqrt{3}$

Hence, the slope of the line is$\sqrt{3}$.