Find the slope of the line parallel to the line joining the points (−4,3) and (2,5).
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Solution
We know that the slope of the line joining two points (x1,y1) and (x2,y2) is:
m=y2−y1x2−x1
Here, the given points are (−4,3) and (2,5), therefore, the slope of the line is:
m1=y2−y1x2−x1=5−32−(−4)=26=13
We also know that if the slope of the two lines are equal that is m1=m2, then the lines are parallel, therefore, the slope m2 of the line parallel to the given line is:
m1=m2=13
Hence, the slope of the line parallel to the given line is13.