Find the slope of the line passing the two given points
(i) $(4, - 8)$ and $(5, - 2)$
(ii) $(0, 0)$ and $(\sqrt{3}, 3)$
(iii) $(2 a, 3 b)$ and $(a, - b)$

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Solution

$\begin{matrix} (i) (4, - 8) (5, - 2) S l o p e (m) = \frac{- 2 + 8}{5 - 4} = \frac{6}{1} = 6 (i i) (0, 0) (\sqrt{3}, 3) S l o p e = \frac{3}{\sqrt{3}} = \sqrt{3} (i i i) (2 a, 3 b) (a, - b) S l o p e = \frac{4 b}{a} \end{matrix}$

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