Find the slope of the line perpendicular to $A B$ if $A = (0, - 5)$ and $B = (- 2, 4)$ .

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Solution

Slope of $A B = \frac{4 - (- 5)}{- 2 - 0} = - \frac{9}{2}$
$∴$ slope of $⊥$ to $A B$
$= - 1 / 9 / - 2 = \frac{2}{9}$

Hence, this is the answer.

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