Finding the slope of the line perpendicular to AB
Given, points are A(0,−5) and B (−2,4).
∵ slope of line AB=y2−y1x2−x1
⇒ slope =4−(−5)−2−0=4+5−2=−92
We know, if two lines are perpendicular, the
product of their slopes is −1.
∴slope of line perpendicular to AB
= −1slope of AB=−1−92=29
Hence, the slope of the line perpendicular to AB is 29.