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Question

Find the slope of the line which is parallel to :

(i) x + 2y + 3 = 0

(ii) x2y31=0

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Solution

(i) x + 2y + 3 = 0

2y = -x - 3

y = fraction numerator negative 1 over denominator 2 end fraction x minus 3 over 2

Slope of this line = fraction numerator negative 1 over denominator 2 end fraction

Slope of the line which is parallel to the given line = Slope of the given line = fraction numerator negative 1 over denominator 2 end fraction

(ii) x over 2 minus y over 3 minus 1 equals 0

y over 3 equals x over 2 minus 1 y equals 3 over 2 x minus 3

Slope of this line =3 over 2

Slope of the line which is parallel to the given line = Slope of the given line = 3 over 2


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