Find the slope of the line which is parallel to :

(i) x + 2y + 3 = 0

(ii) $\frac{x}{2} - \frac{y}{3} - 1 = 0$

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Solution

(i) x + 2y + 3 = 0

2y = -x - 3

y = $fraction numerator negative 1 over denominator 2 end fraction x minus 3 over 2$

Slope of this line = $fraction numerator negative 1 over denominator 2 end fraction$

Slope of the line which is parallel to the given line = Slope of the given line = $fraction numerator negative 1 over denominator 2 end fraction$

(ii)

Slope of this line =

Slope of the line which is parallel to the given line = Slope of the given line =

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Similar questions

Find the slope of the line which is perpendicular to :

(i) $x - \frac{y}{2} + 3 = 0$

(ii) $\frac{x}{3} - 2 y = 4$

(i) Is the line 3x + 4y + 7 = 0 perpendicular to the line 28x - 21y + 50 = 0 ?

(ii) Is the line x - 3y = 4 perpendicular to the line 3x - y = 7 ?

(iii) Is the line 3x + 2y = 5 parallel to the line x + 2y = 1 ?

(iv) Determine x so that the slope of the line through (1, 4) and (x, 2) is 2.

x^{2} + y^{2} = 4

x + 2 y + 3 = 0

x + 2 y + 3 z - 5 = 0 = 3 x + 2 y + z - 5

x - 1 = 2 - y = z - 3

x^{2} + y^{2} = 4

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