Question

Find the slope of the line whose inclination is:​
(iii) ${72}^{\circ }{30}^{\prime }$

Answer 1

Given :
Inclination , $\theta ={72}^{\circ }{30}^{\prime }$
We know that, the slope of a line is given by the $\tan$ of its inclination.
Therefore , slope $=\tan \theta$
$\Rightarrow \text{slope}=\tan {72}^{\circ }{30}^{\prime }$
$\Rightarrow \text{slope}=3.1716$ [From the trigonometric table ]
Hence, the slope of the given line is $3.1716$