Question

Find the slope of the line $x-y+3=0$

Answer 1

Equations of straight lines are in the form

$y=mx+c⟶\left(i\right)$

where,

$m=$ gradient of the line

$c=$ y-intercept (where the graph crosses the y-axis)

Given equation of line-

$x-y+3=0$

$\Rightarrow y=x+3⟶\left(ii\right)$

On comparing ${eq}^n\left(i\right)\&\left(ii\right)$, we get

$m=1$

$c=3$

Hence, slope of line, $x-y+3=0$ is $1$.