Find the slope of the line $y = x^{3} - 3 x$ which is parallel to $2 x + 18 y = 9$ .

2

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7

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9

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- 2

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Solution

The correct options are
A $2$
D $- 2$
$\begin{matrix} y = x^{3} - 3 x \frac{d y}{d x} = 3 x^{2} - 3 T h e n o r m a l i s p a r a l l e l t o l i n e 2 x + 18 y = 9 s o l p e o f t h e n o r m a l = \frac{- 1}{\frac{d y}{d x}} = \frac{- 1}{9} \frac{d y}{d x} = 9 3 x^{2} - 3 = 9 ∴ x = \pm 2 \end{matrix}$

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Similar questions

y = x^{3} - 3 x

y = x^{3} - 3 x

2 x + 18 y = 9

y = x^{3} - 3 x

2 x + 18 y = 9

y = x^{2} - 2 x + 7

2 x - y + 9 = 0

y = x^{2} - 2 x + 7

2 x - y + 9 = 0

5 y - 15 x = 13.

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