Find the slope of the tangent to the curve y=4x2−3x−8 at point (−3,4).
A
27
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B
−27
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C
−29
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D
29
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Solution
The correct option is B−27 The slope of the tangent to the curve y=4x2−3x−8 is given by dydx
So, we have slope as dydx=d(4x2−3x−8)dx=8x−3
Thus, slope of the tangent at point (−3,4) is given as dydx|(−3,4)=(8×(−3)−3)=−27