LCMof18,24,32=288
Thesmallestfourdigitnumberdivisibleby18,24,32=288×4=1152
Hence,requirednumberis1152
Find the smallest 4-digit number which is divisible by 18,24 and 32.
The smallest 4 digit number which is divisible by 18, 24 & 32 is
Find the greatest number of six digit exactly divisible by 18 , 24 and 36.(with steps)
Which is the smallest 3-digit number divisible by 4