Question

Find the smallest among three consecutive odd natural numbers whose sum is $87.$

Answer 1

Let the three consecutive odd natural numbers are $n,n+2$ and $n+4$

It is given that their sum is $87$

So,

$\left(n\right)+(n+2)+(n+4)=87$

$3n+6=87$

$3n=87-6=81$

So, $n=\frac{81}{3}=27$

Smallest no. is $27.$