Question

Find the smallest and the greatest digit so that the number formed is divisible by given divisor:

Answer 1

A number is divisible by $3$ if the sum of its digits is divisible by $3$.

Sum of digits $=8+3+2+5=18$ which is already divisible by $3$.

If $0$ is added then sum is$0+8+3+2+5=18$ which is divisible by $3$.

So, $0$ is the smallest digit so that the number formed is divisible by given divisor.

If $9$ is added then sum is $9+8+3+2+5=27$ which is divisible by $3$.

and $9$ is the greatest digit so that the number formed is divisible by given divisor.