Question

Find the smallest integral $x$ satisfying the inequality $\frac{x-5}{x^2+5x-14}>0$ .

Answer 1

$\frac{x-5}{x^2+5x-14}>0$

$\frac{x-5}{(x+7)(x-2)}>0$

So, $xϵ(-7,2)\cup (5,\infty )$

Smallest integral value of $x=-6$