Question

Find the smallest number by which $135$ must be divided, so that the quotient is a perfect cube.

• A. $3$
• B. $5$
• C. $9$
• D. $15$

Answer 1

The correct option is B $5$

$135=5\times 3\times 3\times 3$
$=(5\times 3^3)$
$={\left(3\right)}^3\times 5$
In the above factorization there is triplet for $5$.
So, $135$ is not a perfect cube.
$\therefore$ $135$ must be divided by $5$ to make the quotient a perfect cube.