Find the smallest number by which 1715 be divided so that the quotient is a perfect cube
For a number to be a perfect cube, its prime factors should be expressed as triplets.
By prime factorization, we get 1715=7×7×7×5
We have three 7’s but only one 5 so we need to divide the number by 5.
∴ We need to divide it by 5, then it becomes cube of 7 i.e 343