Find the smallest number by which 235445 must be divided so that it becomes a perfect square also find the square root of the perfect square so obtained

Open in App

Solution

Factorise 235445
235445 = 5 x 47089 = 5x7 x 6727= 5x7x7x961 = 5x7x7x31x31
So if we divide 235445 by 5 we will get 7x7x31x31 which a perfect square of 7x31= 217.
Answer : 5

Suggest Corrections

Similar questions

Q. By what smallest number must

180

be multiplied so that it becomes a perfect square? Also, find the square root of the number so obtained.

Q. Find the smallest number by which

300

must be multiplied so that it becomes a perfect square. Also, find the square root of the perfect square so obtained.

Find the smallest number by which 1152 must be divided so that it becomes a perfect square. Also, find the number whose square is the resulting number.

Q. Find the smallest number by which 1575 must be divided so that the quotient becomes a perfect square.

Join BYJU'S Learning Program

Find the smallest number by which 235445 must be divided so that it becomes a perfect square also find the square root of the perfect square so obtained

Factorise 235445 235445 = 5 x 47089 = 5x7 x 6727= 5x7x7x961 = 5x7x7x31x31 So if we divide 235445 by 5 we will get 7x7x31x31 which a perfect square of 7x31= 217. Answer : 5

Factorise 235445
235445 = 5 x 47089 = 5x7 x 6727= 5x7x7x961 = 5x7x7x31x31
So if we divide 235445 by 5 we will get 7x7x31x31 which a perfect square of 7x31= 217.
Answer : 5