Find the smallest number by which 2560 must be multiplied so that the product is a perfect cube.
Factorising 2560 into prime factors.
Making them in groups of 3 equal factors, we are left 5
∴ To make it into a group of 3, we have to multiply it by 5×5 i.e. by 25.
Hence, the smallest number by which it is multiplied = 25