iven number is 3645
Write down the prime factors of 3645
3645=5*3*3*3*3*3*3
Organising the prime factors into pairs
3645=(3*3)(3*3)(3*3)*5
We observe that only 5 doesn't exist in pair
So,the smallest number that should be divided from 3645 to make it a perfect square is 5
3645÷5= 729
Thus the resulting number is 729
√729=27
There fore , 27 is the square root of resulting number 729
hope it helped!