Question

Find the smallest number by which $64$ must be divided so that the result is a perfect cube.

Answer 1

$\sqrt[3]{364}=\sqrt[3]{3\underset{–}{2\times 2\times 2}\times \underset{–}{2\times 2\times 2}}=2\times 2=4$
Hence, $64$ is already a perfect cube, so divide it by $1$.