Question

Find the smallest number by which $8788$ must be divided so that the quotient is a perfect cube.

Answer 1

Firstly we need to factorize the number $8788$

After factorization we get,

$\Rightarrow 8788=\underset{–}{2\times 2}\times \underset{–}{13\times 13\times 13}$

We need to group the expanded numbers in a group of three since it has to be a perfect cube.

The number $2$ does not form a triplet. It contains two $2^{\prime }s.$ Hence the number $2\times 2=4$ has to be divided so that the quotient becomes a perfect cube.