Find the smallest number by which the number $88$ must be divided to obtain a perfect cube

11

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $11$
The factor of $88 = 2 \times 2 \times 2 \times 11$
In the expansion, $2$ appears three times and $11$ appears once.
So, to get a perfect square we need to divide $88$ by $11$ .
Hence, the answer is $11$ .

Suggest Corrections

Join BYJU'S Learning Program