Find the smallest number that is completely divisible by 28 and 42.

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Solution

The correct option is B 84
The smallest number that is completely divisible by 28 and 42 is the LCM of the two numbers.

$\begin{matrix} 2 & 28, 42 2 & 14, 21 3 & 7, 21 7 & 7, 7 1, 1 \end{matrix}$

Hence, the LCM of 28 and 42 = $2 \times 2 \times 3 \times 7 = 84$

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