Question

Find the smallest number that is completely divisible by $36$ and $48$.

• A. 36
• B. 144
• C. 288
• D. 72

Answer 1

The correct option is B 144

Prime factorisation of $36$ and $48$:

$36=\text{2}\times \text{2}\times \text{3}\times 3$

$48=\text{2}\times \text{2}\times 2\times 2\times \text{3}$

So, LCM of $36$ and $48$

$=2\times 2\times 2\times 2\times 3\times 3=144$

$144$ is the smallest number that is completely divisible by both $36$ and $48$.