Find the smallest number that is divisible by first 10 natural numbers.

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Solution

Dear student

The first 10 Natural numbers are 1,2,3,4,5,6,7,8,9,10

Find the LCM of 1 to 10
2×2×2×3×3×5×7=2520

Hence the smallest number divisible by first 10 natural number is 2520

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