Question

Find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32

Answer 1

If the difference between the divisor and the remainder is SAME, then there is an easy way of solving the remainder questions.

In this question,

divisor is 28 and remainder is 8. Difference is 20 (28-8)

divisor is 32 and remainder is 12. Difference is 20 (32-12)

You can see that the difference is 20 in both the cases.

Answer Would be:

LCM of divisors - difference ,OR, LCM (28, 32) - 20 = 224 - 20 = 204